SSLC Maths English Medium - Statistics One Mark Questions Online Test
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Maths - Statistics
Maths - Statistics
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- The range of the first 10 prime numbers 2, 3, 5, 7, 11, 13, 17, 19, 23 , 29 is
- 28
- 26
- 29
- 27
- The least value in a collection of data is 14.1. If the range of the collection is 28.4, then the greatest value of the collection is
- 42 . 5
- 43 . 5
- 42 .4
- 42 .1
- The greatest value of a collection of data is 72 and the least value is 28.Then the coefficient of range is
- 44
- 0.72
- 0 .44
- 0. 28
- For a collection of 11 items, ∑x = 132, then the arithmetic mean i
- 11
- 12
- 14
- 13
- For any collection of n items,∑ (x -x̄ ) =
- ∑x
- x̄
- nx̄
- 0
- For any collection of n items, (∑x) - x̄ =
- nx̄
- ( n - 2) x̄
- (n - 1) x̄
- 0
- If t is the standard deviation of x, y. z, then the standard deviation of x + 5, y + 5, z + 5 is
- t/3
- t + 5
- t
- x y z
- If the standard deviation of a set of data is 1.6, then the variance is
- 0 . 4
- 2 . 56
- 1 . 96
- 0 . 04
- If the variance of a data is 12.25, then the S.D is
- 3 . 5
- 3
- 2 . 5
- 3 . 25
- Variance of the first 11 natural numbers is
- √5
- √10
- 5√2
- 10
- The variance of 10, 10, 10, 10, 10 is
- 10
- √10
- 5
- 0
- If the variance of 14, 18, 22, 26, 30 is 32, then the variance of 28, 36,44,52,60 is
- 64
- 128
- 32√2
- 32
- Standard deviation of a collection of data is 2√2 . If each value is multiplied by 3,then the standard deviation of the new data is
- √12
- 4√2
- 6√2
- 9√2
- Given ∑(x - x̄)² = 48 , x̄ = 20 , and n = 12 The coefficient of variation is
- 25
- 20
- 30
- 10
- Mean and standard deviation of a data are 48 and 12 respectively. The coefficient of variation is
- 42
- 25
- 28
- 48
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